Const
Definition for singly-linked list. class ListNode { val: number next: ListNode | null constructor(val?: number, next?: ListNode | null) { this.val = (val===undefined ? 0 : val) this.next = (next===undefined ? null : next) } }
/**
* Definition for singly-linked list.
* class ListNode {
* val: number
* next: ListNode | null
* constructor(val?: number, next?: ListNode | null) {
* this.val = (val===undefined ? 0 : val)
* this.next = (next===undefined ? null : next)
* }
* }
*/
function mergeTwoLists(list1: ListNode | null, list2: ListNode | null): ListNode | null {
const dummy = new ListNode(-1, null);
let tail = dummy;
let l1 = list1;
let l2 = list2;
while (l1 && l2) {
if (l1.val <= l2.val) {
tail.next = l1;
l1 = l1.next;
}
else {
tail.next = l2;
l2 = l2.next;
}
tail = tail.next;
}
tail.next = l1 ?? l2;
return dummy.next;
};
21.合并两个有序链表
将两个升序链表合并为一个新的 升序 链表并返回。新链表是通过拼接给定的两个链表的所有节点组成的。
示例 1:
输入:
list1 = [1,2,4], list2 = [1,3,4]
输出:
[1,1,2,3,4,4]
示例 2:
输入:
list1 = [], list2 = []
输出:
[]
示例 3:
输入:
list1 = [], list2 = [0]
输出:
[0]
提示:
[0, 50]
-100 <= Node.val <= 100
list1
和list2
均按 非递减顺序 排列